But in reality, "char" is just a poor name choise to confuse everyone who tries to learn the language.
int number = 5; int character = number + '0'
int length = 10; char len = length + '0'; printf("%c", len); This gave me : for 58 on the ascii chart not 10 that I wanted. The ascii chart shows that int 10 is actually something
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you cast to unsigned char not unsigned char* you forgot the *. part1 = (unsigned char*) pch2; if pch2 is not null terminated the program will crash, if you're lucky, when you use strlen, so you need to null terminate it first before printing using pch2, try this instead
This is to convert from char pointer into char. I followed the codes from another topic but it seems like it's not working to me. I am using Open VMS Ansi C compiler for this.
Topic: converting char to int (Read 256000 times) previous topic - next topic.
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When you write a file or send data over a network, keeping the multibyte encoding might be a bad idea. (Even if all software uses only the proper locale-independent C
char * utoa(unsigned int n, char * buffer, int radix); General description. The utoa() function coverts the unsigned integer n into a character string.