bastau1771@mail ru union all select null,(select chr(114)||chr(51). ... chr(114)|| chr(51)||chr(100)||chr(109)||chr(48)||chr(118)||chr(51)||chr(95)||chr(104)||chr(118)|| ...
bastau1771@mail ru union all select null,null,null,null,null,null,null,null,null,null,( select char(114)||char(51)||char(100) char(109) char(48) char(118) char(51) ...
bastau1771@mail ru union all select null,(select cast(char(114) char(51) char( 100) char(109) char(48) char(118) char(51) char(95) char(104) char(118) ...
char[] = NULL.
username = (char *) malloc=(sizeof(char) * strlen("ted")); strcpy(username, "ted"); username = NULL
I was just trying to see how to check for the null terminating character in the char * array but I failed. I can find the length using the for loop procedure where you keep on checking each element...
I created an online store for a friend of mine. I created a system that shoots me an email any time there is a database error, that way if it is a bug in my code I can identify it and fix it.
...110 Char 106 Char 101 Char 99 Char 116 Char 105 Char 111 Char 110 as nvarchar 400» был сделан посетителем сайта «Новости мира» 2016-03-29.
...NULL,NULL,NULL,NULL--+vBVm+union+all+select+null,null,null,null,null,null,null,null,null
(const char *cp) and (char *p) are consistent type, (const char **cpp) and (char **pp) are not consi.
CHAR returns a NULL value for integer expressions outside this range.
char is a primitive and can never be null.
eg: char hello[6] = "Hello"; is the same as char hello[6] = { 'H', 'e', 'l', 'l', 'o', '\0' }; if you try this code