Применение UNION ALL дает другой результат, так как дубликаты не скрываются. Выполнение запроса: (SELECT * FROM sales2005) UNION ALL ( SELECT * FROM sales2006);. даст следующий результат, выводимый без ...
7 авг 2017 ... BusinessEntityID WHERE LastName = 'Johnson'; GO SELECT pp.LastName, pp. FirstName, e.JobTitle INTO dbo.EmployeeThree FROM Person.Person AS pp JOIN HumanResources.Employee AS e ON e.BusinessEntityID = pp. BusinessEntityID WHERE LastName = 'Johnson'; GO -- Union ALL SELECT ...
SELECT snum, sname FROM Salespeople WHERE city = 'London' UNION SELECT cnum, cname FROM Customers WHERE city = 'London'; и получить вывод .... Вы можете получить нечто похожее ( в некоторых программах SQL, используя UNION ALL вместо просто UNION, наподобие этого: SELECT snum , city ...
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